Graph f x 3x
WebAlgebra Graph f (x)= (3x)/ (x^2-16) f (x) = 3x x2 − 16 f ( x) = 3 x x 2 - 16 Find where the expression 3x (x+4)(x−4) 3 x ( x + 4) ( x - 4) is undefined. x = −4,x = 4 x = - 4, x = 4 WebAlgebra Graph f (x)=3x^2-5 f (x) = 3x2 − 5 f ( x) = 3 x 2 - 5 Find the properties of the given parabola. Tap for more steps... Direction: Opens Up Vertex: (0,−5) ( 0, - 5) Focus: (0,−59 12) ( 0, - 59 12) Axis of Symmetry: x = 0 x = 0 Directrix: y = −61 12 y = - 61 12
Graph f x 3x
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WebGraphing y =: x*ln(x) x^3+3x^2+3x x^3-3x^2-9x -x^3+3x^2-4 Integral of d{x}: tan3x Derivative of: tan3x Identical expressions; ... Graph of the function intersects the axis X … WebNov 23, 2024 · The transformation would be reflected on the y-axis and horizontally compressed by -(1/3). This is because since the original function is f(x) and the …
Webg(x) = x3 → f (x) = x3 g ( x) = x 3 → f ( x) = x 3 The horizontal shift depends on the value of h h. The horizontal shift is described as: f (x) = f (x+h) f ( x) = f ( x + h) - The graph is shifted to the left h h units. f (x) = f (x−h) f ( x) = f ( x - h) - … WebAlgebra Graph f(x)=1/x Step 1 Find where the expressionis undefined. Step 2 Consider the rational functionwhere is the degreeof the numeratorand is the degreeof the denominator. 1. If , then the x-axis, , is the horizontalasymptote. 2. If …
WebGraph f (x) 3x^2-6x-1. plot at least 5 points. Of those 5 points, state the vertex point, whether the vertex point is maximum or minimum and the equation of axis of symmetry. This question is from textbook algebra II Found 2 solutions by Earlsdon, stanbon: Answer by Earlsdon (6294) ( Show Source ): You can put this solution on YOUR website! Graph: WebTo find the x x -intercepts, we can solve the equation f (x)=0 f (x) = 0. The x x -intercepts of the graph of y=f (x) y = f (x) are \left (\dfrac23,0\right) (32,0) and (-2,0) (−2,0). Our work …
WebFeb 24, 2015 · Points of maximum or minimum are found by setting the first derivative equal to zero: f '(x) = 3x2 −6x and 3x2 − 6x = 0 gives: 3x(x −2) = 0 and x = 0 and x = 2 When x = 0 y = 0 and when x = 2 y = − 4 Setting the second derivative equal to zero will give us inflection point (s): f ''(x) = 6x −6 and 6x −6 = 0 so that x = 1 and y = − 2 And finally:
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